8(j-4)=3(2j+15)

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Solution for 8(j-4)=3(2j+15) equation: 



8(j-4)=3(2j+15)

We move all terms to the left:

8(j-4)-(3(2j+15))=0

We multiply parentheses

8j-(3(2j+15))-32=0



We calculate terms in parentheses: -(3(2j+15)), so:

3(2j+15)

We multiply parentheses

6j+45

Back to the equation:

-(6j+45)



We get rid of parentheses

8j-6j-45-32=0

We add all the numbers together, and all the variables

2j-77=0

We move all terms containing j to the left, all other terms to the right

2j=77

j=77/2

j=38+1/2

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