8(k+3)-2(-3+3k)=2-2k+7+7k

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Solution for 8(k+3)-2(-3+3k)=2-2k+7+7k equation: 



8(k+3)-2(-3+3k)=2-2k+7+7k

We move all terms to the left:

8(k+3)-2(-3+3k)-(2-2k+7+7k)=0

We add all the numbers together, and all the variables

8(k+3)-2(3k-3)-(5k+9)=0

We multiply parentheses

8k-6k-(5k+9)+24+6=0

We get rid of parentheses

8k-6k-5k-9+24+6=0

We add all the numbers together, and all the variables

-3k+21=0

We move all terms containing k to the left, all other terms to the right

-3k=-21

k=-21/-3

k=+7

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