8(k-6)+2(k+4)=7k-1-6

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Solution for 8(k-6)+2(k+4)=7k-1-6 equation: 



8(k-6)+2(k+4)=7k-1-6

We move all terms to the left:

8(k-6)+2(k+4)-(7k-1-6)=0

We add all the numbers together, and all the variables

8(k-6)+2(k+4)-(7k-7)=0

We multiply parentheses

8k+2k-(7k-7)-48+8=0

We get rid of parentheses

8k+2k-7k+7-48+8=0

We add all the numbers together, and all the variables

3k-33=0

We move all terms containing k to the left, all other terms to the right

3k=33

k=33/3

k=11

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