8(l-1)+1=2(l+2)+1

Solution for 8(l-1)+1=2(l+2)+1 equation:

8(l-1)+1=2(l+2)+1

We move all terms to the left:

8(l-1)+1-(2(l+2)+1)=0

We multiply parentheses

8l-(2(l+2)+1)-8+1=0


We calculate terms in parentheses: -(2(l+2)+1), so:

2(l+2)+1

We multiply parentheses

2l+4+1

We add all the numbers together, and all the variables

2l+5

Back to the equation:

-(2l+5)


We add all the numbers together, and all the variables

8l-(2l+5)-7=0

We get rid of parentheses

8l-2l-5-7=0

We add all the numbers together, and all the variables

6l-12=0

We move all terms containing l to the left, all other terms to the right

6l=12

l=12/6

l=2