8(m+2)-3(m-4)=8+6(m-7)

Solution for 8(m+2)-3(m-4)=8+6(m-7) equation:

8(m+2)-3(m-4)=8+6(m-7)

We move all terms to the left:

8(m+2)-3(m-4)-(8+6(m-7))=0

We multiply parentheses

8m-3m-(8+6(m-7))+16+12=0


We calculate terms in parentheses: -(8+6(m-7)), so:

8+6(m-7)

determiningTheFunctionDomain
6(m-7)+8

We multiply parentheses

6m-42+8

We add all the numbers together, and all the variables

6m-34

Back to the equation:

-(6m-34)


We add all the numbers together, and all the variables

5m-(6m-34)+28=0

We get rid of parentheses

5m-6m+34+28=0

We add all the numbers together, and all the variables

-1m+62=0

We move all terms containing m to the left, all other terms to the right

-m=-62

m=-62/-1

m=+62