8(m-2)=-2(1+m)+8m

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Solution for 8(m-2)=-2(1+m)+8m equation: 



8(m-2)=-2(1+m)+8m

We move all terms to the left:

8(m-2)-(-2(1+m)+8m)=0

We add all the numbers together, and all the variables

8(m-2)-(-2(m+1)+8m)=0

We multiply parentheses

8m-(-2(m+1)+8m)-16=0



We calculate terms in parentheses: -(-2(m+1)+8m), so:

-2(m+1)+8m

We add all the numbers together, and all the variables

8m-2(m+1)

We multiply parentheses

8m-2m-2

We add all the numbers together, and all the variables

6m-2

Back to the equation:

-(6m-2)



We get rid of parentheses

8m-6m+2-16=0

We add all the numbers together, and all the variables

2m-14=0

We move all terms containing m to the left, all other terms to the right

2m=14

m=14/2

m=7

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