8(n+1)-(n+2)=n+12+3n

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Solution for 8(n+1)-(n+2)=n+12+3n equation:



8(n+1)-(n+2)=n+12+3n
We move all terms to the left:
8(n+1)-(n+2)-(n+12+3n)=0
We add all the numbers together, and all the variables
8(n+1)-(n+2)-(4n+12)=0
We multiply parentheses
8n-(n+2)-(4n+12)+8=0
We get rid of parentheses
8n-n-4n-2-12+8=0
We add all the numbers together, and all the variables
3n-6=0
We move all terms containing n to the left, all other terms to the right
3n=6
n=6/3
n=2

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