8(n-1)/5=(3n-4)/2

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Solution for 8(n-1)/5=(3n-4)/2 equation: 



8(n-1)/5=(3n-4)/2

We move all terms to the left:

8(n-1)/5-((3n-4)/2)=0

We calculate fractions


8n/()+(-((3n-4)*5)/()=0



We calculate terms in parentheses: +(-((3n-4)*5)/(), so:

-((3n-4)*5)/(

We multiply all the terms by the denominator


-((3n-4)*5)



We calculate terms in parentheses: -((3n-4)*5), so:

(3n-4)*5

We multiply parentheses

15n-20

Back to the equation:

-(15n-20)



We get rid of parentheses

-15n+20

Back to the equation:

+(-15n+20)



We get rid of parentheses

8n/()-15n+20=0

We multiply all the terms by the denominator


8n-15n*()+20*()=0

We add all the numbers together, and all the variables

8n-15n*()=0

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