8(n-5)-6=4+10(1+2n)

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Solution for 8(n-5)-6=4+10(1+2n) equation: 



8(n-5)-6=4+10(1+2n)

We move all terms to the left:

8(n-5)-6-(4+10(1+2n))=0

We add all the numbers together, and all the variables

8(n-5)-(4+10(2n+1))-6=0

We multiply parentheses

8n-(4+10(2n+1))-40-6=0



We calculate terms in parentheses: -(4+10(2n+1)), so:

4+10(2n+1)

determiningTheFunctionDomain
10(2n+1)+4

We multiply parentheses

20n+10+4

We add all the numbers together, and all the variables

20n+14

Back to the equation:

-(20n+14)



We add all the numbers together, and all the variables

8n-(20n+14)-46=0

We get rid of parentheses

8n-20n-14-46=0

We add all the numbers together, and all the variables

-12n-60=0

We move all terms containing n to the left, all other terms to the right

-12n=60

n=60/-12

n=-5

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