8(n-6)=-32+4n

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Solution for 8(n-6)=-32+4n equation:



8(n-6)=-32+4n
We move all terms to the left:
8(n-6)-(-32+4n)=0
We add all the numbers together, and all the variables
8(n-6)-(4n-32)=0
We multiply parentheses
8n-(4n-32)-48=0
We get rid of parentheses
8n-4n+32-48=0
We add all the numbers together, and all the variables
4n-16=0
We move all terms containing n to the left, all other terms to the right
4n=16
n=16/4
n=4

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