8(q+3)-6(q-3)=2(q+21)

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Solution for 8(q+3)-6(q-3)=2(q+21) equation:



8(q+3)-6(q-3)=2(q+21)
We move all terms to the left:
8(q+3)-6(q-3)-(2(q+21))=0
We multiply parentheses
8q-6q-(2(q+21))+24+18=0
We calculate terms in parentheses: -(2(q+21)), so:
2(q+21)
We multiply parentheses
2q+42
Back to the equation:
-(2q+42)
We add all the numbers together, and all the variables
2q-(2q+42)+42=0
We get rid of parentheses
2q-2q-42+42=0
We add all the numbers together, and all the variables
=0
q=0/1
q=0

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