8(q+3)-6(q-3)=2(q+21)

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Solution for 8(q+3)-6(q-3)=2(q+21) equation: 



8(q+3)-6(q-3)=2(q+21)

We move all terms to the left:

8(q+3)-6(q-3)-(2(q+21))=0

We multiply parentheses

8q-6q-(2(q+21))+24+18=0



We calculate terms in parentheses: -(2(q+21)), so:

2(q+21)

We multiply parentheses

2q+42

Back to the equation:

-(2q+42)



We add all the numbers together, and all the variables

2q-(2q+42)+42=0

We get rid of parentheses

2q-2q-42+42=0

We add all the numbers together, and all the variables

=0

q=0/1

q=0

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