8(r-3)=r-36+4r

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Solution for 8(r-3)=r-36+4r equation: 



8(r-3)=r-36+4r

We move all terms to the left:

8(r-3)-(r-36+4r)=0

We add all the numbers together, and all the variables

8(r-3)-(5r-36)=0

We multiply parentheses

8r-(5r-36)-24=0

We get rid of parentheses

8r-5r+36-24=0

We add all the numbers together, and all the variables

3r+12=0

We move all terms containing r to the left, all other terms to the right

3r=-12

r=-12/3

r=-4

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