8(r-5)-7(r-1)=2(r+6)

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Solution for 8(r-5)-7(r-1)=2(r+6) equation:



8(r-5)-7(r-1)=2(r+6)
We move all terms to the left:
8(r-5)-7(r-1)-(2(r+6))=0
We multiply parentheses
8r-7r-(2(r+6))-40+7=0
We calculate terms in parentheses: -(2(r+6)), so:
2(r+6)
We multiply parentheses
2r+12
Back to the equation:
-(2r+12)
We add all the numbers together, and all the variables
r-(2r+12)-33=0
We get rid of parentheses
r-2r-12-33=0
We add all the numbers together, and all the variables
-1r-45=0
We move all terms containing r to the left, all other terms to the right
-r=45
r=45/-1
r=-45

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