8(r-5)-7(r-1)=2(r+6)

Solution for 8(r-5)-7(r-1)=2(r+6) equation:

8(r-5)-7(r-1)=2(r+6)

We move all terms to the left:

8(r-5)-7(r-1)-(2(r+6))=0

We multiply parentheses

8r-7r-(2(r+6))-40+7=0


We calculate terms in parentheses: -(2(r+6)), so:

2(r+6)

We multiply parentheses

2r+12

Back to the equation:

-(2r+12)


We add all the numbers together, and all the variables

r-(2r+12)-33=0

We get rid of parentheses

r-2r-12-33=0

We add all the numbers together, and all the variables

-1r-45=0

We move all terms containing r to the left, all other terms to the right

-r=45

r=45/-1

r=-45