8(r-8)=-40-4r

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Solution for 8(r-8)=-40-4r equation: 



8(r-8)=-40-4r

We move all terms to the left:

8(r-8)-(-40-4r)=0

We add all the numbers together, and all the variables

8(r-8)-(-4r-40)=0

We multiply parentheses

8r-(-4r-40)-64=0

We get rid of parentheses

8r+4r+40-64=0

We add all the numbers together, and all the variables

12r-24=0

We move all terms containing r to the left, all other terms to the right

12r=24

r=24/12

r=2

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