8(s+2)=4-(-8s-12)

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Solution for 8(s+2)=4-(-8s-12) equation: 



8(s+2)=4-(-8s-12)

We move all terms to the left:

8(s+2)-(4-(-8s-12))=0

We multiply parentheses

8s-(4-(-8s-12))+16=0



We calculate terms in parentheses: -(4-(-8s-12)), so:

4-(-8s-12)

determiningTheFunctionDomain
-(-8s-12)+4

We get rid of parentheses

8s+12+4

We add all the numbers together, and all the variables

8s+16

Back to the equation:

-(8s+16)



We get rid of parentheses

8s-8s-16+16=0

We add all the numbers together, and all the variables

=0

s=0/1

s=0

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