8(t+12)-3(+-4)=6(t-7+8)

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Solution for 8(t+12)-3(+-4)=6(t-7+8) equation:



8(t+12)-3(+-4)=6(t-7+8)
We move all terms to the left:
8(t+12)-3(+-4)-(6(t-7+8))=0
We add all the numbers together, and all the variables
8(t+12)-(6(t+1))-3(-4)=0
We add all the numbers together, and all the variables
8(t+12)-(6(t+1))+12=0
We multiply parentheses
8t-(6(t+1))+96+12=0
We calculate terms in parentheses: -(6(t+1)), so:
6(t+1)
We multiply parentheses
6t+6
Back to the equation:
-(6t+6)
We add all the numbers together, and all the variables
8t-(6t+6)+108=0
We get rid of parentheses
8t-6t-6+108=0
We add all the numbers together, and all the variables
2t+102=0
We move all terms containing t to the left, all other terms to the right
2t=-102
t=-102/2
t=-51

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