8(t+2)-3(t+12)=(t-7)+8

Solution for 8(t+2)-3(t+12)=(t-7)+8 equation:

8(t+2)-3(t+12)=(t-7)+8

We move all terms to the left:

8(t+2)-3(t+12)-((t-7)+8)=0

We multiply parentheses

8t-3t-((t-7)+8)+16-36=0


We calculate terms in parentheses: -((t-7)+8), so:

(t-7)+8

We get rid of parentheses

t-7+8

We add all the numbers together, and all the variables

t+1

Back to the equation:

-(t+1)


We add all the numbers together, and all the variables

5t-(t+1)-20=0

We get rid of parentheses

5t-t-1-20=0

We add all the numbers together, and all the variables

4t-21=0

We move all terms containing t to the left, all other terms to the right

4t=21

t=21/4

t=5+1/4