8(t+2)-3(t-12)=6(t-7)+8

Solution for 8(t+2)-3(t-12)=6(t-7)+8 equation:

8(t+2)-3(t-12)=6(t-7)+8

We simplify the equation to the form, which is simple to understand 
8(t+2)-3(t-12)=6(t-7)+8

Reorder the terms in parentheses
+(+8t+16)-3*(t-12)=6*(t-7)+8

Remove unnecessary parentheses
+8t+16-3+*(+t-12+)=+6+*(+t-7+)+8

Reorder the terms in parentheses
+8t+16+(-3t+36)=6*(t-7)+8

Remove unnecessary parentheses
+8t+16-3t+36=+6+*(+t-7+)+8

Reorder the terms in parentheses
+8t+16-3t+36=+(+6t-42)+8

Remove unnecessary parentheses
+8t+16-3t+36=+6t-42+8

We move all terms containing t to the left and all other terms to the right. 
+8t-3t-6t=-42+8-16-36

We simplify left and right side of the equation. 
-1t=-86

We divide both sides of the equation by -1 to get t. 
t=86