8(t+2)-3(t-2)=6(t-7)+8

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Solution for 8(t+2)-3(t-2)=6(t-7)+8 equation:



8(t+2)-3(t-2)=6(t-7)+8
We move all terms to the left:
8(t+2)-3(t-2)-(6(t-7)+8)=0
We multiply parentheses
8t-3t-(6(t-7)+8)+16+6=0
We calculate terms in parentheses: -(6(t-7)+8), so:
6(t-7)+8
We multiply parentheses
6t-42+8
We add all the numbers together, and all the variables
6t-34
Back to the equation:
-(6t-34)
We add all the numbers together, and all the variables
5t-(6t-34)+22=0
We get rid of parentheses
5t-6t+34+22=0
We add all the numbers together, and all the variables
-1t+56=0
We move all terms containing t to the left, all other terms to the right
-t=-56
t=-56/-1
t=+56

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