8(t+2)-3(t-4)=6(t-4)=6(t-7)+8

Solution for 8(t+2)-3(t-4)=6(t-4)=6(t-7)+8 equation:

8(t+2)-3(t-4)=6(t-4)=6(t-7)+8

We move all terms to the left:

8(t+2)-3(t-4)-(6(t-4))=0

We multiply parentheses

8t-3t-(6(t-4))+16+12=0


We calculate terms in parentheses: -(6(t-4)), so:

6(t-4)

We multiply parentheses

6t-24

Back to the equation:

-(6t-24)


We add all the numbers together, and all the variables

5t-(6t-24)+28=0

We get rid of parentheses

5t-6t+24+28=0

We add all the numbers together, and all the variables

-1t+52=0

We move all terms containing t to the left, all other terms to the right

-t=-52

t=-52/-1

t=+52