8(t+2)-3(t-4)=6(t-7)+9

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Solution for 8(t+2)-3(t-4)=6(t-7)+9 equation: 



8(t+2)-3(t-4)=6(t-7)+9

We move all terms to the left:

8(t+2)-3(t-4)-(6(t-7)+9)=0

We multiply parentheses

8t-3t-(6(t-7)+9)+16+12=0



We calculate terms in parentheses: -(6(t-7)+9), so:

6(t-7)+9

We multiply parentheses

6t-42+9

We add all the numbers together, and all the variables

6t-33

Back to the equation:

-(6t-33)



We add all the numbers together, and all the variables

5t-(6t-33)+28=0

We get rid of parentheses

5t-6t+33+28=0

We add all the numbers together, and all the variables

-1t+61=0

We move all terms containing t to the left, all other terms to the right

-t=-61

t=-61/-1

t=+61

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