8(t+2)-3(t-4)=6t-7)+8

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Solution for 8(t+2)-3(t-4)=6t-7)+8 equation: 



8(t+2)-3(t-4)=6t-7)+8

We move all terms to the left:

8(t+2)-3(t-4)-(6t-7)+8)=0

We add all the numbers together, and all the variables

8(t+2)-3(t-4)-(6t-7)=0

We multiply parentheses

8t-3t-(6t-7)+16+12=0

We get rid of parentheses

8t-3t-6t+7+16+12=0

We add all the numbers together, and all the variables

-1t+35=0

We move all terms containing t to the left, all other terms to the right

-t=-35

t=-35/-1

t=+35

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