8(t+2)-3(t-4=6(t-70+8

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Solution for 8(t+2)-3(t-4=6(t-70+8 equation:



8(t+2)-3(t-4=6(t-70+8
We move all terms to the left:
8(t+2)-3(t-4-(6(t-70+8)=0
We add all the numbers together, and all the variables
8(t+2)-3(t-4-(6(t-62)=0
We multiply parentheses
8t-3(t-4-(6(t-62)+16=0

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