8(t+2)=-3(t-4)=6(t-7)+8

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Solution for 8(t+2)=-3(t-4)=6(t-7)+8 equation:



8(t+2)=-3(t-4)=6(t-7)+8
We move all terms to the left:
8(t+2)-(-3(t-4))=0
We multiply parentheses
8t-(-3(t-4))+16=0
We calculate terms in parentheses: -(-3(t-4)), so:
-3(t-4)
We multiply parentheses
-3t+12
Back to the equation:
-(-3t+12)
We get rid of parentheses
8t+3t-12+16=0
We add all the numbers together, and all the variables
11t+4=0
We move all terms containing t to the left, all other terms to the right
11t=-4
t=-4/11
t=-4/11

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