8(t+3)-7(t+2)=11

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Solution for 8(t+3)-7(t+2)=11 equation: 



8(t+3)-7(t+2)=11

We move all terms to the left:

8(t+3)-7(t+2)-(11)=0

We multiply parentheses

8t-7t+24-14-11=0

We add all the numbers together, and all the variables

t-1=0

We move all terms containing t to the left, all other terms to the right

t=1

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