8(t-1)=4(t+2)-t

Solution for 8(t-1)=4(t+2)-t equation:

8(t-1)=4(t+2)-t

We move all terms to the left:

8(t-1)-(4(t+2)-t)=0

We multiply parentheses

8t-(4(t+2)-t)-8=0


We calculate terms in parentheses: -(4(t+2)-t), so:

4(t+2)-t

We add all the numbers together, and all the variables

-1t+4(t+2)

We multiply parentheses

-1t+4t+8

We add all the numbers together, and all the variables

3t+8

Back to the equation:

-(3t+8)


We get rid of parentheses

8t-3t-8-8=0

We add all the numbers together, and all the variables

5t-16=0

We move all terms containing t to the left, all other terms to the right

5t=16

t=16/5

t=3+1/5