8(t-2)-3(t-4)=6(t-7)+8

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Solution for 8(t-2)-3(t-4)=6(t-7)+8 equation:


8(t-2)-3(t-4)=6(t-7)+8

We simplify the equation to the form, which is simple to understand
8(t-2)-3(t-4)=6(t-7)+8

Reorder the terms in parentheses
+(+8t-16)-3*(t-4)=6*(t-7)+8

Remove unnecessary parentheses
+8t-16-3+*(+t-4+)=+6+*(+t-7+)+8

Reorder the terms in parentheses
+8t-16+(-3t+12)=6*(t-7)+8

Remove unnecessary parentheses
+8t-16-3t+12=+6+*(+t-7+)+8

Reorder the terms in parentheses
+8t-16-3t+12=+(+6t-42)+8

Remove unnecessary parentheses
+8t-16-3t+12=+6t-42+8

We move all terms containing t to the left and all other terms to the right.
+8t-3t-6t=-42+8+16-12

We simplify left and right side of the equation.
-1t=-30

We divide both sides of the equation by -1 to get t.
t=30

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