8(t-3)+4t=6(2t+1-10)

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Solution for 8(t-3)+4t=6(2t+1-10) equation: 



8(t-3)+4t=6(2t+1-10)

We move all terms to the left:

8(t-3)+4t-(6(2t+1-10))=0

We add all the numbers together, and all the variables

8(t-3)+4t-(6(2t-9))=0

We add all the numbers together, and all the variables

4t+8(t-3)-(6(2t-9))=0

We multiply parentheses

4t+8t-(6(2t-9))-24=0



We calculate terms in parentheses: -(6(2t-9)), so:

6(2t-9)

We multiply parentheses

12t-54

Back to the equation:

-(12t-54)



We add all the numbers together, and all the variables

12t-(12t-54)-24=0

We get rid of parentheses

12t-12t+54-24=0

We add all the numbers together, and all the variables

30!=0

There is no solution for this equation

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