8(t-3)+4t=6(2t+3)-9

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Solution for 8(t-3)+4t=6(2t+3)-9 equation: 



8(t-3)+4t=6(2t+3)-9

We move all terms to the left:

8(t-3)+4t-(6(2t+3)-9)=0

We add all the numbers together, and all the variables

4t+8(t-3)-(6(2t+3)-9)=0

We multiply parentheses

4t+8t-(6(2t+3)-9)-24=0



We calculate terms in parentheses: -(6(2t+3)-9), so:

6(2t+3)-9

We multiply parentheses

12t+18-9

We add all the numbers together, and all the variables

12t+9

Back to the equation:

-(12t+9)



We add all the numbers together, and all the variables

12t-(12t+9)-24=0

We get rid of parentheses

12t-12t-9-24=0

We add all the numbers together, and all the variables

-33!=0

There is no solution for this equation

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