8(t-3)+6t=7(2t+4)-10

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Solution for 8(t-3)+6t=7(2t+4)-10 equation: 



8(t-3)+6t=7(2t+4)-10

We move all terms to the left:

8(t-3)+6t-(7(2t+4)-10)=0

We add all the numbers together, and all the variables

6t+8(t-3)-(7(2t+4)-10)=0

We multiply parentheses

6t+8t-(7(2t+4)-10)-24=0



We calculate terms in parentheses: -(7(2t+4)-10), so:

7(2t+4)-10

We multiply parentheses

14t+28-10

We add all the numbers together, and all the variables

14t+18

Back to the equation:

-(14t+18)



We add all the numbers together, and all the variables

14t-(14t+18)-24=0

We get rid of parentheses

14t-14t-18-24=0

We add all the numbers together, and all the variables

-42!=0

There is no solution for this equation

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