8(t-4)+4t=6(2t+3)-12

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Solution for 8(t-4)+4t=6(2t+3)-12 equation:


Simplifying
8(t + -4) + 4t = 6(2t + 3) + -12

Reorder the terms:
8(-4 + t) + 4t = 6(2t + 3) + -12
(-4 * 8 + t * 8) + 4t = 6(2t + 3) + -12
(-32 + 8t) + 4t = 6(2t + 3) + -12

Combine like terms: 8t + 4t = 12t
-32 + 12t = 6(2t + 3) + -12

Reorder the terms:
-32 + 12t = 6(3 + 2t) + -12
-32 + 12t = (3 * 6 + 2t * 6) + -12
-32 + 12t = (18 + 12t) + -12

Reorder the terms:
-32 + 12t = 18 + -12 + 12t

Combine like terms: 18 + -12 = 6
-32 + 12t = 6 + 12t

Add '-12t' to each side of the equation.
-32 + 12t + -12t = 6 + 12t + -12t

Combine like terms: 12t + -12t = 0
-32 + 0 = 6 + 12t + -12t
-32 = 6 + 12t + -12t

Combine like terms: 12t + -12t = 0
-32 = 6 + 0
-32 = 6

Solving
-32 = 6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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