8(t-4)/7=t-3

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Solution for 8(t-4)/7=t-3 equation: 


t in (-oo:+oo)

(8*(t-4))/7 = t-3 // - t-3

(8*(t-4))/7-t+3 = 0

(8*(t-4))/7+(7*(-t))/7+(3*7)/7 = 0

8*(t-4)+7*(-t)+3*7 = 0

t-32+21 = 0

t-11 = 0

(t-11)/7 = 0

(t-11)/7 = 0 // * 7

t-11 = 0

t-11 = 0 // + 11

t = 11

t = 11

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