8(t-5)+4t=6(2t+2)-11

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Solution for 8(t-5)+4t=6(2t+2)-11 equation: 


Simplifying
8(t + -5) + 4t = 6(2t + 2) + -11

Reorder the terms:
8(-5 + t) + 4t = 6(2t + 2) + -11
(-5 * 8 + t * 8) + 4t = 6(2t + 2) + -11
(-40 + 8t) + 4t = 6(2t + 2) + -11

Combine like terms: 8t + 4t = 12t
-40 + 12t = 6(2t + 2) + -11

Reorder the terms:
-40 + 12t = 6(2 + 2t) + -11
-40 + 12t = (2 * 6 + 2t * 6) + -11
-40 + 12t = (12 + 12t) + -11

Reorder the terms:
-40 + 12t = 12 + -11 + 12t

Combine like terms: 12 + -11 = 1
-40 + 12t = 1 + 12t

Add '-12t' to each side of the equation.
-40 + 12t + -12t = 1 + 12t + -12t

Combine like terms: 12t + -12t = 0
-40 + 0 = 1 + 12t + -12t
-40 = 1 + 12t + -12t

Combine like terms: 12t + -12t = 0
-40 = 1 + 0
-40 = 1

Solving
-40 = 1

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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