8(t-6)+2(5t+4)=17(t-1)+1

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Solution for 8(t-6)+2(5t+4)=17(t-1)+1 equation: 



8(t-6)+2(5t+4)=17(t-1)+1

We move all terms to the left:

8(t-6)+2(5t+4)-(17(t-1)+1)=0

We multiply parentheses

8t+10t-(17(t-1)+1)-48+8=0



We calculate terms in parentheses: -(17(t-1)+1), so:

17(t-1)+1

We multiply parentheses

17t-17+1

We add all the numbers together, and all the variables

17t-16

Back to the equation:

-(17t-16)



We add all the numbers together, and all the variables

18t-(17t-16)-40=0

We get rid of parentheses

18t-17t+16-40=0

We add all the numbers together, and all the variables

t-24=0

We move all terms containing t to the left, all other terms to the right

t=24

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