8(tan(2x))-16(cos(x))=0

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Solution for 8(tan(2x))-16(cos(x))=0 equation:


Simplifying
8(tan(2x)) + -16(cos(x)) = 0

Remove parenthesis around (2x)
8(ant * 2x) + -16(cos(x)) = 0

Reorder the terms for easier multiplication:
8(2ant * x) + -16(cos(x)) = 0

Multiply ant * x
8(2antx) + -16(cos(x)) = 0

Remove parenthesis around (2antx)
8 * 2antx + -16(cos(x)) = 0

Multiply 8 * 2
16antx + -16(cos(x)) = 0

Multiply cos * x
16antx + -16(cosx) = 0

Solving
16antx + -16cosx = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '16cosx' to each side of the equation.
16antx + -16cosx + 16cosx = 0 + 16cosx

Combine like terms: -16cosx + 16cosx = 0
16antx + 0 = 0 + 16cosx
16antx = 0 + 16cosx
Remove the zero:
16antx = 16cosx

Divide each side by '16ntx'.
a = cn-1ost-1

Simplifying
a = cn-1ost-1

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