8(u-8)+2(2u-2)=4

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Solution for 8(u-8)+2(2u-2)=4 equation: 



8(u-8)+2(2u-2)=4

We move all terms to the left:

8(u-8)+2(2u-2)-(4)=0

We multiply parentheses

8u+4u-64-4-4=0

We add all the numbers together, and all the variables

12u-72=0

We move all terms containing u to the left, all other terms to the right

12u=72

u=72/12

u=6

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