8(v+1)-4=4(2v-3)

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Solution for 8(v+1)-4=4(2v-3) equation: 



8(v+1)-4=4(2v-3)

We move all terms to the left:

8(v+1)-4-(4(2v-3))=0

We multiply parentheses

8v-(4(2v-3))+8-4=0



We calculate terms in parentheses: -(4(2v-3)), so:

4(2v-3)

We multiply parentheses

8v-12

Back to the equation:

-(8v-12)



We add all the numbers together, and all the variables

8v-(8v-12)+4=0

We get rid of parentheses

8v-8v+12+4=0

We add all the numbers together, and all the variables

16!=0

There is no solution for this equation

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