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8(v+1)-4v=2(2v+4)-12
We move all terms to the left:
8(v+1)-4v-(2(2v+4)-12)=0
We add all the numbers together, and all the variables
-4v+8(v+1)-(2(2v+4)-12)=0
We multiply parentheses
-4v+8v-(2(2v+4)-12)+8=0
We calculate terms in parentheses: -(2(2v+4)-12), so:We add all the numbers together, and all the variables
2(2v+4)-12
We multiply parentheses
4v+8-12
We add all the numbers together, and all the variables
4v-4
Back to the equation:
-(4v-4)
4v-(4v-4)+8=0
We get rid of parentheses
4v-4v+4+8=0
We add all the numbers together, and all the variables
12!=0
There is no solution for this equation
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