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8(v+2)-2v=2(3v+2)-12
We move all terms to the left:
8(v+2)-2v-(2(3v+2)-12)=0
We add all the numbers together, and all the variables
-2v+8(v+2)-(2(3v+2)-12)=0
We multiply parentheses
-2v+8v-(2(3v+2)-12)+16=0
We calculate terms in parentheses: -(2(3v+2)-12), so:We add all the numbers together, and all the variables
2(3v+2)-12
We multiply parentheses
6v+4-12
We add all the numbers together, and all the variables
6v-8
Back to the equation:
-(6v-8)
6v-(6v-8)+16=0
We get rid of parentheses
6v-6v+8+16=0
We add all the numbers together, and all the variables
24!=0
There is no solution for this equation
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