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8(v+2)-2v=2(3v=3)-10
We move all terms to the left:
8(v+2)-2v-(2(3v)=0
We add all the numbers together, and all the variables
-2v+8(v+2)-(23v=0
We multiply parentheses
-2v+8v-(23v+16=0
We add all the numbers together, and all the variables
6v-(23v+16=0
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