8(v+2)-2v=3(2v+2)-12

Solution for 8(v+2)-2v=3(2v+2)-12 equation:

Simplifying
8(v + 2) + -2v = 3(2v + 2) + -12

Reorder the terms:
8(2 + v) + -2v = 3(2v + 2) + -12
(2 * 8 + v * 8) + -2v = 3(2v + 2) + -12
(16 + 8v) + -2v = 3(2v + 2) + -12

Combine like terms: 8v + -2v = 6v
16 + 6v = 3(2v + 2) + -12

Reorder the terms:
16 + 6v = 3(2 + 2v) + -12
16 + 6v = (2 * 3 + 2v * 3) + -12
16 + 6v = (6 + 6v) + -12

Reorder the terms:
16 + 6v = 6 + -12 + 6v

Combine like terms: 6 + -12 = -6
16 + 6v = -6 + 6v

Add '-6v' to each side of the equation.
16 + 6v + -6v = -6 + 6v + -6v

Combine like terms: 6v + -6v = 0
16 + 0 = -6 + 6v + -6v
16 = -6 + 6v + -6v

Combine like terms: 6v + -6v = 0
16 = -6 + 0
16 = -6

Solving
16 = -6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.