8(v+2)-2v=3(2v+2)-8

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Solution for 8(v+2)-2v=3(2v+2)-8 equation: 



8(v+2)-2v=3(2v+2)-8

We move all terms to the left:

8(v+2)-2v-(3(2v+2)-8)=0

We add all the numbers together, and all the variables

-2v+8(v+2)-(3(2v+2)-8)=0

We multiply parentheses

-2v+8v-(3(2v+2)-8)+16=0



We calculate terms in parentheses: -(3(2v+2)-8), so:

3(2v+2)-8

We multiply parentheses

6v+6-8

We add all the numbers together, and all the variables

6v-2

Back to the equation:

-(6v-2)



We add all the numbers together, and all the variables

6v-(6v-2)+16=0

We get rid of parentheses

6v-6v+2+16=0

We add all the numbers together, and all the variables

18!=0

There is no solution for this equation

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