8(v+2)-2v=3(2v+3)-12

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Solution for 8(v+2)-2v=3(2v+3)-12 equation: 


Simplifying
8(v + 2) + -2v = 3(2v + 3) + -12

Reorder the terms:
8(2 + v) + -2v = 3(2v + 3) + -12
(2 * 8 + v * 8) + -2v = 3(2v + 3) + -12
(16 + 8v) + -2v = 3(2v + 3) + -12

Combine like terms: 8v + -2v = 6v
16 + 6v = 3(2v + 3) + -12

Reorder the terms:
16 + 6v = 3(3 + 2v) + -12
16 + 6v = (3 * 3 + 2v * 3) + -12
16 + 6v = (9 + 6v) + -12

Reorder the terms:
16 + 6v = 9 + -12 + 6v

Combine like terms: 9 + -12 = -3
16 + 6v = -3 + 6v

Add '-6v' to each side of the equation.
16 + 6v + -6v = -3 + 6v + -6v

Combine like terms: 6v + -6v = 0
16 + 0 = -3 + 6v + -6v
16 = -3 + 6v + -6v

Combine like terms: 6v + -6v = 0
16 = -3 + 0
16 = -3

Solving
16 = -3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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