8(v+2)=28+6v

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Solution for 8(v+2)=28+6v equation: 



8(v+2)=28+6v

We move all terms to the left:

8(v+2)-(28+6v)=0

We add all the numbers together, and all the variables

8(v+2)-(6v+28)=0

We multiply parentheses

8v-(6v+28)+16=0

We get rid of parentheses

8v-6v-28+16=0

We add all the numbers together, and all the variables

2v-12=0

We move all terms containing v to the left, all other terms to the right

2v=12

v=12/2

v=6

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