8(v+3-5(v-2)=1+6v+2v+3

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Solution for 8(v+3-5(v-2)=1+6v+2v+3 equation:



8(v+3-5(v-2)=1+6v+2v+3
We move all terms to the left:
8(v+3-5(v-2)-(1+6v+2v+3)=0
We add all the numbers together, and all the variables
8(v+3-5(v-2)-(8v+4)=0

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