8(v+4)-4v=2(2v+3)-22

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Solution for 8(v+4)-4v=2(2v+3)-22 equation:


Simplifying
8(v + 4) + -4v = 2(2v + 3) + -22

Reorder the terms:
8(4 + v) + -4v = 2(2v + 3) + -22
(4 * 8 + v * 8) + -4v = 2(2v + 3) + -22
(32 + 8v) + -4v = 2(2v + 3) + -22

Combine like terms: 8v + -4v = 4v
32 + 4v = 2(2v + 3) + -22

Reorder the terms:
32 + 4v = 2(3 + 2v) + -22
32 + 4v = (3 * 2 + 2v * 2) + -22
32 + 4v = (6 + 4v) + -22

Reorder the terms:
32 + 4v = 6 + -22 + 4v

Combine like terms: 6 + -22 = -16
32 + 4v = -16 + 4v

Add '-4v' to each side of the equation.
32 + 4v + -4v = -16 + 4v + -4v

Combine like terms: 4v + -4v = 0
32 + 0 = -16 + 4v + -4v
32 = -16 + 4v + -4v

Combine like terms: 4v + -4v = 0
32 = -16 + 0
32 = -16

Solving
32 = -16

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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