8(v-1)=6v-12

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Solution for 8(v-1)=6v-12 equation: 



8(v-1)=6v-12

We move all terms to the left:

8(v-1)-(6v-12)=0

We multiply parentheses

8v-(6v-12)-8=0

We get rid of parentheses

8v-6v+12-8=0

We add all the numbers together, and all the variables

2v+4=0

We move all terms containing v to the left, all other terms to the right

2v=-4

v=-4/2

v=-2

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