8(v-2)=5(v+3)+8

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Solution for 8(v-2)=5(v+3)+8 equation: 



8(v-2)=5(v+3)+8

We move all terms to the left:

8(v-2)-(5(v+3)+8)=0

We multiply parentheses

8v-(5(v+3)+8)-16=0



We calculate terms in parentheses: -(5(v+3)+8), so:

5(v+3)+8

We multiply parentheses

5v+15+8

We add all the numbers together, and all the variables

5v+23

Back to the equation:

-(5v+23)



We get rid of parentheses

8v-5v-23-16=0

We add all the numbers together, and all the variables

3v-39=0

We move all terms containing v to the left, all other terms to the right

3v=39

v=39/3

v=13

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