8(x+)-3(x-4)=6(x-7)

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Solution for 8(x+)-3(x-4)=6(x-7) equation: 



8(x+)-3(x-4)=6(x-7)

We move all terms to the left:

8(x+)-3(x-4)-(6(x-7))=0

We add all the numbers together, and all the variables

8(+x)-3(x-4)-(6(x-7))=0

We multiply parentheses

8x-3x-(6(x-7))+12=0



We calculate terms in parentheses: -(6(x-7)), so:

6(x-7)

We multiply parentheses

6x-42

Back to the equation:

-(6x-42)



We add all the numbers together, and all the variables

5x-(6x-42)+12=0

We get rid of parentheses

5x-6x+42+12=0

We add all the numbers together, and all the variables

-1x+54=0

We move all terms containing x to the left, all other terms to the right

-x=-54

x=-54/-1

x=+54

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