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8(x+1)+1=3x+5(2+x)
We move all terms to the left:
8(x+1)+1-(3x+5(2+x))=0
We add all the numbers together, and all the variables
8(x+1)-(3x+5(x+2))+1=0
We multiply parentheses
8x-(3x+5(x+2))+8+1=0
We calculate terms in parentheses: -(3x+5(x+2)), so:We add all the numbers together, and all the variables
3x+5(x+2)
We multiply parentheses
3x+5x+10
We add all the numbers together, and all the variables
8x+10
Back to the equation:
-(8x+10)
8x-(8x+10)+9=0
We get rid of parentheses
8x-8x-10+9=0
We add all the numbers together, and all the variables
-1!=0
There is no solution for this equation
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